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#h'(x)=f'(x)g(x)f(x)g'(x)# We are ask to find #h'(1)#, or by the product rule #h'(1)=f'(1)g(1)f(1)g'(1)# The values of the functions must be #f(1)=2# and #g(1)=4/3# Remember the derivative gives the slope of any given point, but as we can see in the figures these must correspond, to the slope of the line, which goes through theConsider the following table of values for a linear function f of X is equal to MX plus B and an exponential function G of X is equal to a times R to the X write the equation for each function and so they give us for each xvalue what f of X is and what G of X is and we need to figure out the equation for each function and type them in over here so I copy and pasted this problem on myFirstly, we must find the composite function fg (x) in terms of x before we solve it In order to do this, we can break down the function in the following way fg (x) = f g (x) = f (x5) As you can see, we have broken down fg (x) into a function of g within a
